Print first 50 numbers using break

JavaScript Conversations
#1 
for(var i=1;i<=100;i++)
{
//write your code here...

}
print first 50 [1,2,3.....50]; // using break;
1 Like
#2 

for(var i=1;i<=100;i++)
{
//write your code here...
console.log(i);
if(i>50){
break;
}
2 Likes
#3

for(var i=1;i<=100;i++)
{
//write your code here…
if(i<=50){
console.log(i);
}
break;
}
print first 50 [1,2,3…50]; // using break;

1 Like
#4

@pavana.two.r ,

Your logic is correct,

for(var i=1;i<=100;i++)
{
if(i>50){
break;
}
  console.log(i)
}
#5

@khssbhagavan1919 ,

Your code will work properly if you comment out the break.

for(var i=1;i<=100;i++)
{
//write your code here…
if(i<=50){
console.log(i);
}
//break;
}
#6

The alternative solution for this problem

for(let i=1;i<=100;i++)
{
if(i==51){ // It breaks the loop and continues executing the code after the loop.
  break;
}
console.log(i);
}